The earth is flat and we never went to the moon--Part II
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I'm not trying to make lite of your work, I just don't get it.
After reading it, my thought was, "So what?"
What's the argument?
It seems you managed to make something where you could actually draw the triangles and measure the angles with a protractor, thereby confirming at least part of those numbers with your own eyes.
Yes?
Everyone
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If I extended my graph in the other direction I would have 800 miles, Chicago to New York City.
From 20 miles up over Youngstown Ohio, you could look north across Lake Erie and Lake Ontario into Canada then turn your head left and see Chicago, turn your head right and see New York City. You would be looking 40 miles down at the horizon almost 400 miles into the distance in all directions from eye level.
--Dave
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If I extended my graph in the other direction I would have 800 miles, Chicago to New York City.
From 20 miles up over Youngstown Ohio, you could look north across Lake Erie and Lake Ontario into Canada then turn your head left and see Chicago, turn your head right and see New York City. You would be looking 40 miles down at the horizon almost 400 miles into the distance in all directions from eye level.
--Dave
Yes when you have side a and side b at the 90 degree point you can get side c and the angle from viewer.
The question in my mind is how far below eye level would a 40 mile drop at 390 miles away look like? You said yourself it would be noticable. If they put a telephoto lens on a camera instead of a fish eye we would certainly see this drop much better or see if there was no drop.
--Dave
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When you click on my graph you get a sense of the drop from the left end at my mark 20 miles up to 40 miles down at the horizon at the right end.
--Dave
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When will Dave address the "flat earth map" making Australia TWICE as big as it actually is?
Because I've been a professional graphic artist I will work on producing graphs to scale that will show the curvature of earth at a six feet to maybe 1 mile elevation, a 35000 foot elevation to a 100000 foot elevation.
A visualization is as important as the numbers in determining if we see the flat earth horizon at eye level or if we are looking down at the horizon of a globe. I want to see both sides of this horizon argument and I don't want to be accused of misrepresenting either one.
--Dave
The battle for the horizon is primary in FE vs GE. The size of continents is secondary.
--Dave
Hey Dave, on your graph, pick a random spot on it and calculate the length of a segment on that curve that, at scale, would be about 6 miles in length. Then tell me how curved that segment looks, or if it's relatively flat.
I'm working on short distances now. My question is how far can we really see into the distance. If I'm correct we can see the horizon at 3 miles away, but we cannot see ships on the horizon at that distance without a telescope or telephoto lens.
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Is this ship as seen from shore 3 miles away or closer? It's taken from about 5 to 6 feet up, I think.
--Dave
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The Right-angled Triangles Calculator
b=3959 miles (radius of Earth)
c=3999 miles (radius plus altitude)
40 miles altitude yields an 8.11° (angle A) down angle to the horizon line. That's not a huge angle by any means and I'd wager that your brain would still make it feel like it was straight in front of your eyes unless you were paying very careful attention. You'd really want and Abney Level or some other sort of instrument.
But that's not to say you couldn't get an idea of what it looks like. Just download some sort of app on your phone and find something off in the distance that's 8° above the horizon and see the difference.
Right, and try to imagine how flat that angle is going to seem when you blow it up to life size!
If you do it right, you're fixing to be a former flat-Earther.
At an altitude of 10 km (33,000 ft, the typical cruising altitude of an airliner) the mathematical curvature of the horizon is about 0.056, the same curvature of the rim of circle with a radius of 10 m that is viewed from 56 cm directly above the center of the circle. However, the apparent curvature is less than that due to refraction of light in the atmosphere and because the horizon is often masked by high cloud layers that reduce the altitude above the visual surface.
https://en.wikipedia.org/wiki/Horizon#Curvature_of_the_horizon
Assuming that exactly none of the ship is hidden by the horizon and that the camera is six feet about the surface of the water and assuming standard refraction, the ship would be approximately 3.25 miles away.
https://www.metabunk.org/curve/
I'm having trouble being blocked with some of my replies.
I think one would notice a horizon drop of 13.2 miles from a commercial flight at 35000 feet
--Dave
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We can't see 6 miles from 6 ft height, we can see 3 miles. The earth drops 6 feet in three miles, add 6 feet to height of viewer and we have 12 feet. So at six feet eye level we are looking down 12 feet to the horizon 3 miles away. That's not much of a curvature and it would be relatively flat. But knowing how far away a ship is from viewer is important to know.
--Dave
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Nonsense Dave. EVERY incontrovertible argument is a nail in the coffin of the "flat earth mode" (which is no model at all).
Dave, what's the diameter of a circle with a 3 mile radius?
Ok, the horizon is a biggest nail.
Perspective vs no perspective is vital to this debate.
--Dave
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No Dave, horizon is not the "biggest nail". It's just one of your favorites because you think that you have proof, though you hardly even understand it.
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:french:
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